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A stone is thrown in a vertically upward direction with a velocity of 5 m/s. If the acceleration of the stone during its motion is 10 m/s in the downward direction , what will be the height attained by the stone and how much time will it take to reach there? please reply, waiting.......

Answer»

v=0 and U is negative⇔v=u + gt⇔so time is 0.02 seconds0= - 5 + (-10) * TWE KNOW that v^2-u^2=2as or 2ghso 0² - (- 5)² = 2 * (10) * h⇒h = 1.25m



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