A stone is thrown horizontally at a speed of 12.0 m/s from the top of

1.	A stone is thrown horizontally at a speed of 12.0 m/s from the top of a cliff 92.1 m high. The fall took 4.34 s. How far from the base of the cliff does the stone strike the ground?
Answer» ong>ANSWER: Taking the VERTICAL COMPONENT of motion we can assume that the initial velocity is zero so: s = 1 2 g t 2 ∴ t = √ 2 s g t = √ 2 × 80 9.8 t = 4.04 s (B) The horizontal component of velocity is constant so: Distance = speed x time ∴ d = 30 × 4.04 = 121.2 m Explanation: pls follow me and Mark me as branliest pls And give me thanks

A stone is thrown horizontally at a speed of 12.0 m/s from the top of a cliff 92.1 m high. The fall took 4.34 s. How far from the base of the cliff does the stone strike the ground?

Answer»

ong>ANSWER:

Taking the VERTICAL COMPONENT of motion we can assume that the initial velocity is zero so:

∴

√

9.8

4.04

(B)

The horizontal component of velocity is constant so:

Distance = speed x time

∴

4.04

121.2

Explanation:

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A stone is thrown horizontally at a speed of 12.0 m/s from the top of a cliff 92.1 m high. The fall took 4.34 s. How far from the base of the cliff does the stone strike the ground?

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