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a stone is thrown downwards with velocity 20 m/s from the top of a tower of height 40m. At the same time another stone is projected upwards from the ground along the same line, with the same velocity 20 m/s. when and where do they meet. |
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Answer» Answer: Sy = UT - 1/2 gt² h=Sy = 20 sin 30° × 5 - 1/2 × 10 × (5)² h=50 - 125 = -75m ( MINUS sign just indicate that the displacement is in downward DIRECTION ) Hmax = u² sin² O/ 2g = (20)² sin² 30°/ 2×10 = 5m Hence, maximum height attained by projectile = h + Hmax = 75×5 = 80m |
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