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A stone is released into the river from a bridge. It takes 4s for the stone to touch the river’s water surface. Compute the height of the bridge from the water level. |
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Answer» Given : Initial speed=u= 0 m/s time=t=5sec Case 1) distance travelled = height of BRIDGE=h m From second equation of MOTION: s=ut+1/2at²h =0xt +1/2 9.8 X 5 x5h =122.5m ∴The height of the bridge from water level is 122.5m Case II) Distance travelled in 4sec = (1/2x9.8x4x4) =16x4.9 =78.4 m Distance travelled in last second : =Distance travelled in 5sec - distance travelled in 4 sec=122.5 -78.4=44.1m ∴The distance covered by STONE in the last second is 44.1m |
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