A stone is projected from the ground with velocity 25m/s . After 1.25

1.	A stone is projected from the ground with velocity 25m/s . After 1.25 sec,it is at the highest point of its trajectory . The angle of the projection of stone is
Answer» Explanation: let US ASSUME ,(u=vel) g=10 and A is the angle time to REACH HIGHEST point is=usinA/g usinA/g=1.25 as given u=25m/s 25sinA=12.5 sinA=1/2 angle A=60° hope it helps you

A stone is projected from the ground with velocity 25m/s . After 1.25 sec,it is at the highest point of its trajectory . The angle of the projection of stone is

Answer»

Explanation:

let US ASSUME ,(u=vel) g=10 and A is the angle

time to REACH HIGHEST point is=usinA/g

usinA/g=1.25

as given u=25m/s

25sinA=12.5

sinA=1/2

angle A=60°

hope it helps you

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A stone is projected from the ground with velocity 25m/s . After 1.25 sec,it is at the highest point of its trajectory . The angle of the projection of stone is​

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A stone is projected from the ground with velocity 25m/s . After 1.25 sec,it is at the highest point of its trajectory . The angle of the projection of stone is