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A stone is placed at the bottom of lake of depth 10 m. Refractive index of water of lake is μ=(1+y10) where y is depth of water from surface. A person looks at stone normally, then depth at which stone appears to him in meters is (ln 2=0.693) |
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Answer» A stone is placed at the bottom of lake of depth 10 m. Refractive index of water of lake is μ=(1+y10) where y is depth of water from surface. A person looks at stone normally, then depth at which stone appears to him in meters is (ln 2=0.693) |
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