1.

A stone is dropped from the top of a tree covers 6m height in last 0.2s of fall.find height of tree​

Answer»

Let it will take T time to cover the WHOLE length

so we can say

H = \frac{1}{2}gT^2H=21gT2

now in last 0.2 s it will cover 6 m

H - 6 = \frac{1}{2}g(T - 0.2)^2H−6=21g(T−0.2)2

now by above two equations

\frac{1}{2}gT^2 - 6 = \frac{1}{2}g(T-2)^221gT2−6=21g(T−2)2

\frac{1}{2}g(2T - 2)(2) = 621g(2T−2)(2)=6

T = 1.3 sT=1.3s

now the height of the TREE is

H = \frac{1}{2}*10*1.3^2H=21∗10∗1.32

H = 8.45 MH=8.45m


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