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A stone is dropped from the top of a tower travel 135 m in the last second of its journey the height of the |
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Answer» tion:Let total time be nLast SECOND = N-1Apply 4th LAW of motion For n second u+a/2(2n-1)For (n-1) second u+a/2(2(n-1)-1)u+a/2(2n-3)u=0 a= 10 m/s² tower HEIGHT =135 m0+10/2(2n-3)=13510n-15=135n=15 sec |
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