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a stone is dropped from the top of a tower of height 100M. the stone penetrates in the sand on the ground through a distance of 2m. calculate the retardation of the stone |
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Answer» the stone is being dropped from the top of a tower of hright 100 m. which means the potential ENERGY is being converted to kinetic energy.just before hitting the sand:potential energy = kinetic enegy mgh = 1\2 mu2u² = 2mgh\mu² = 2ghu² = 2 × 9.8 × 100 u² = 1960and we also know that:v² = u² + 2asas the retardation is NEGATIVE the sign will get CHANGED to:v² = u² - 2as we will take the final velocity as 0 because the stone comes to rest after hitting the sand.0 = 1960 - 2 × a × 2 ( given: the stone penetrates in the sand on the ground through a distance of 2M )-4a = -1960a= 490 m/S-2Explanation:Hope so u are satisfied with the answerIf so please follow......... |
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