1.

A stone is dropped from the adge of a roof.find the speed of the stone at 2 second after the stone was dropped.

Answer» FINDING acceleration
a = vf - vi \div t
vf =0m/s
vi=0m/s
t=2sec

hence
a=0.5m/s^2

now, for distance
2as = vf {}^{2} - vi {}^{2}
2(0.5)s=0^2-0^2
1s=0
s=0/1
s = 0m
for speed
s = distance \div time

speed=0/2
hence s=0m/s


Discussion

No Comment Found

Related InterviewSolutions