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A stone is allowed to fall from the top of tower 100 m high and at the same time another stone is projected vertically upward from the ground with the velocity of 25 matter calculate when and where two stone are meeting |
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Answer» Let "t" = time after which both stones MEET"S" = distance travelled by the STONE DROPPED from the top of tower(100-S) = distance travelled by the projected stone.◆ i) For stone dropped from the top of tower-S = 0 + 1/2 (-10) t²or, S = 5t²◆ ii) For stone projected upward(100 - S) = 25t + 1/2 (-10) t²= 25t - 5t²Adding i) and ii) , We get100 = 25tor t = 4 sTherefore, Two stones will meet after 4 s.◆ ¡¡¡) Put value of t = 4 s in Equation i) , we getS = 5 × 16= 80 m.Thus , both the stone will meet at a distance of 80 m from the top of tower.PLEASE MARK THIS ANSWER AS BRAINLIEST ANSWER |
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