1.

A stone is allowed to fall from a top of a tower 100 m high and at the same time another stone is projected vertically upwards from the ground with a velocity of 25 m/s.The two stones will melt after :

Answer»

40s
0.4S
4s
0.04s

Solution :`X = (1)/(2) G t^(2) "" . . . (1) `
` s = ut - (1)/(2) g t^(2)`
`100 - x = 25 t - (1)/(2) g t^(2) "". . . (2)`
Adding (1) and(2) we get ,
100 = 25 t
`:. t = (100)/(25) = 4s`


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