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a stone dropped in a well hits the water surface after 2s . what is the depth of the the well and with what speed will the stone hit the water surface ? assume the uniform acceleration due to gravity to be 9.8m/s^2. |
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Answer» HIIII dear________❤️❤️❤️❤️ good evening____________________ ✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️ U = 0 t = 2sec a = -g = 9.8m/s^2 S = ut + 1/2at^2 S = 0 + (-19.6) S = -19.6m V = u + at v = -19.6 m/s as body is falling from a height so , depth of the well will be 19.6m and speed with which it STRIKES the SURFACE of water = 19.6m/s |
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