A stone dropped from top of tower of height 300 m high splashes into water off. near base of our when is the splash pad at the top given speed of sound in air is 340 m per second

A stone dropped from top of tower of height 300 m high splashes into w

1.	A stone dropped from top of tower of height 300 m high splashes into water off. near base of our when is the splash pad at the top given speed of sound in air is 340 m per second
Answer» Height of the tower, s = 300 m Initial velocity of the stone, u = 0 Acceleration, a = G = 9.8 m/s2 Speed of sound in air = 340 m/s The time (t1) TAKEN by the stone to strike the water in the pond can be calculated using the second equation of motion, as: s = ut1 + 1/2 gt12 300 = 0 + 1/2 × 9.8 × t12 ∴ t1 = √300 × 2/9.8 = 7.82 s Time taken by the sound to reach the TOP of the tower, t2 = 300/340 = 0.88 s Therefore, the time after which splash is HEARD, t = t1 + t2 = 7.82 + 0.88 = 8.7 s.

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A stone dropped from top of tower of height 300 m high splashes into water off. near base of our when is the splash pad at the top given speed of sound in air is 340 m per second

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