A steel wire when bent in the form of a square encloses an area of 121

1.	A steel wire when bent in the form of a square encloses an area of 121 cm² . The same wire is bent in the form of a circle. Find the area of the circle.
Answer» Given :- A steel WIRE when bent in the FORM of a square encloses an area of 121 cm² The same wire is bent in the form of a circle. To FIND :- The area of the circle. Solution :- We know that, a = Area r = Radius d = Diameter Given that, Area of the square (a) = 121 cm² By the formula, $\underline{\boxed{\sf Area \ of \ circle= \pi r^{2}}}$ $\underline{\boxed{\sf Area \ of \ square=2 \times Side}}$ Substituting them, 121 cm² = a² So, a = 11 cm Thus, Each side of the square = 11 cm Now, $\underline{\boxed{\sf Perimeter \ of \ square = 4a }}$ By substituting, $\sf = 4 \times 11 = 44 \ cm$ According to the question, Perimeter of the square = Circumference of the circle We know, $\underline{\boxed{\sf Circumference \ of \ circle=2 \pi r}}$ Now, further $\sf 4a = 2 \pi r$ $\sf 44=2\dfrac{22}{7} r$ $\sf r=7 \ cm$ Next, $\underline{\boxed{\sf Area \ of \ circle=\pi r^{2}}}$ Substituting their values, $\sf =\dfrac{22}{7} \times 7 \times 7$ $\sf =<klux>154</klux> \ cm^{2}$ Therefore, the area of the circle is 154 cm²