A steel wire of length, mass and cross sectional area of 1 m, 0.1 kg and 10−6 m2 respectively is rigidly fixed at both ends. Now, if the temperature of the wire is lowered by 20∘C and transverse waves are setup by plucking the wire at 0.25 m from one end. Assuming that the wire vibrates with minimum number of loops possible, for such case the frequency of vibration in Hz is 11x. Then the value of x is . Write upto two digits after the decimal point. [αsteel=1.21×10−5 /∘C and Y=2.0×1011 N/m2 ]

A steel wire of length, mass and cross sectional area of 1 m, 0.1 kg a

1.	A steel wire of length, mass and cross sectional area of 1 m, 0.1 kg and 10−6 m2 respectively is rigidly fixed at both ends. Now, if the temperature of the wire is lowered by 20∘C and transverse waves are setup by plucking the wire at 0.25 m from one end. Assuming that the wire vibrates with minimum number of loops possible, for such case the frequency of vibration in Hz is 11x. Then the value of x is . Write upto two digits after the decimal point. [αsteel=1.21×10−5 /∘C and Y=2.0×1011 N/m2 ]
Answer» A steel wire of length, mass and cross sectional area of 1 $m$ , 0.1 $k g$ and $10^{- 6} m^{2}$ respectively is rigidly fixed at both ends. Now, if the temperature of the wire is lowered by $20^{\circ} C$ and transverse waves are setup by plucking the wire at 0.25 $m$ from one end. Assuming that the wire vibrates with minimum number of loops possible, for such case the frequency of vibration in $H z$ is $11 x$ . Then the value of $x$ is . Write upto two digits after the decimal point. [ $α_{s t e e l} = 1.21 \times 10^{- 5} /^{\circ} C$ and $Y = 2.0 \times 10^{11} N / m^{2}$ ]

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