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A steel wire of 2mm in diameter is stretched by applying a force of 72N. Find the stress in the wire. |
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Answer» SOLUTION :`r = 1 xx 10^(-3)m, F= 72N` The stress `= (F)/(A)= (F)/(pi r^(2))= (72)/(pi(1 xx 10^(-3))^(2))` ` =(72)/(pi xx 10^(-6))= 2.292 xx 10^(7)Nm^(-2)`. |
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