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A steel wire having a radius of 2.0 mm, carrying a load of 4 kg, is hanging from a ceiling. Given that g = 3.1π ms⁻² , what will be the tensile stress that would be developed in the wire?(A) 6.2 × 10⁶ Nm⁻²(B) 4.8 × 10⁶ Nm⁻²(C) 5.2 × 10⁶ Nm⁻²(D) 3.1 × 10⁶ Nm⁻² |
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Answer» Option (D) 3.1 × 10⁶ Nm⁻² Explanation: Tensile stress in WIRE will be = Cross section Area / Tensile force = 4 * 3.1 π / π * 4 * 10^-6 HOPE THAT IT WAS HELPFUL!!!! MARK IT THE BRAINLIEST IF IT REALLY WAS!!!! |
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