A steel rod is 4 cm in diameter at 30°C. A brass ring has an interior diameter of 3.992 cm at 30° C. In order that the ring just slides on to the steel rod, the common temperature of the two rods should be ( alpha_(s) = 11 xx 10^(-6) //1^(@) C, alpha_(b) = 19 xx 10^(-6) // 1^(@) C)

A steel rod is 4 cm in diameter at 30°C. A brass ring has an interior

1.	A steel rod is 4 cm in diameter at 30°C. A brass ring has an interior diameter of 3.992 cm at 30° C. In order that the ring just slides on to the steel rod, the common temperature of the two rods should be ( alpha_(s) = 11 xx 10^(-6) //1^(@) C, alpha_(b) = 19 xx 10^(-6) // 1^(@) C)
Answer» 200°C 350°C 280°C 300°C Answer :C