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A steam of water flowing horizontally with a speed of 15 ms-1 gushes out of a tube of cross-sectional area 10-2 m2, and hits at a vertical wall nearby. What is the force exerted on the wall by the impact of water, assuming it does not rebound? |
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Answer» Volume of water striking the wall per second = v x A = 15 x 10-2 = 0.15 m-3 s-1 Mass of water hitting wall per second = 9 x v x A = 1000 x 0.15 kg s-1 = 150 kg s-1 Initial momentum of water per second = 150 x 150 = 2250 kg ms-1 Final momentum of water per second = 0 (There is no rebound of water) Magnitude of force = Rate of change of momentum = 2250 N |
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