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A steam engine intakes 50g of steam at 100°C per minute and cools it down to 20°C. If latent heat of vaporization of steam is 540 cal g1, then the heat rejected by the steam engine per minute is × 103 cal. |
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Answer» Answer is 31 Heat rejected = mLf + mSΔT = (50 x 540) + 50 (1) (100-20) = 31000 Cal = 31 x 103 Cal |
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