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a stationary shell explodes into two fragments having masses in the ratio 1 is to 2 the heavier fragment attains kinetic energy of hundred J. Kinetic energy released in explosion..​

Answer»

300JExplanation:DEAR STUDENT, Let mass of pieces are m1=m and m2=2mApplying conservation of MOMENTUM. m1v1=m2v2⇒mv1=2mv2⇒v1=2v2 Now,  ⇒1/2m2(v2)2=100⇒1/2×2m×(v1/2)2=100⇒1/2m1(v1)2=100×12×4=200 JTotal KE = 300 JRegards



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