A star can be considered as spherical ball of hot gas of radius R. Inside the star, the density of the gas is rho_(r) at radius r and mass of the gas within this region is M_(r). A star in it's prime age is said to be under quilibrium due to gravitational pull and outward radiation pressure (p). consider the shell of thikness dr as in the figure of previous question. if the pressure on this shell is dp then the correc equation is (G is universal gravitational constant)

A star can be considered as spherical ball of hot gas of radius R. Ins

1.	A star can be considered as spherical ball of hot gas of radius R. Inside the star, the density of the gas is rho_(r) at radius r and mass of the gas within this region is M_(r). A star in it's prime age is said to be under quilibrium due to gravitational pull and outward radiation pressure (p). consider the shell of thikness dr as in the figure of previous question. if the pressure on this shell is dp then the correc equation is (G is universal gravitational constant)
Answer» <P>`(dp)/(dr)=-(GM_(R))/(r^(2))rhor` `(dp)/(dr)=(GM_(r))/(r^(2))rhor` `(dp)/(dr)=-2/3(GM_(r))/(r^(2))rhor` `(dp)/(dr)=2/3(GM_(r))/(r^(2))rhor` Solution :`((GM_(r))/(r^(2)))=rho_(r)4pi^(2)dr` `(P)(4pir^(2))-(p+dp)(4pir^(2))` `=(GM)/(r^(2))=sum_(1)4pi^(2)dr` `-dp=(GM_(r)rho_(r)dr)/(r^(2))` `(dp)/(dr)=-(GM_(r))/(r^(2))rho_(r)`