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A square wire loop with sides 0.5 m is placed with its plane perpendicular to the magnetic field. The resistance of the loop is `5Omega`. The rate at which the magnetic induction should be changed so that a current of 0.1 A is induced in the loop isA. 4 T/sB. 3 T/sC. 2 T/sD. 1 T/s |
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Answer» Correct Answer - C `e=(dphi)/(dt)` `IR=(AdB)/(dt)` `(dB)/(dt)=(IR)/(A)=(0.1xx5)/(0.25)=2T//s` |
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