1.

A square plate of mass 120 g and edge 5.0 cm rotates about one of the edges. If it has a uniform angular acceleration of 0.20 rad/s². what torque acts on the plate.?

Answer»

Given in the question :-


Angular acceleration , α = 0.20

Mass M = 120 g or 0.12 kg

Edge a = 5.0 cm or 0.05 m


Moment of INERTIA of PLATE when LINE passing by centre and parallel to the edge

I =Ma²/12


Moment of Inertia (Plate edge)


I' = I+M(a/2)^2

= \frac{Ma^2}{12}+\frac{ Ma^2}{4}

=Ma²/3

Now putting the values,

=(0.12 × 0.05 × 0.05)/3

= 0.0001 kg.m²


Torque (plate) = I'α


=0.0001 × 0.20

=2 x 10⁻⁵ N.m



Hope it Helps :-)


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