Saved Bookmarks
| 1. |
A square plate of 0.1 m side moves parallel to a second plate with a velocity of `0.1 m//s`, both plates being immersed in water. If the viscous force is 0.002 N and the coefficient of viscosity is 0.01 poise , distance between the plates in m isA. `0.1`B. `0.05`C. `0.005`D. `0.0005` |
|
Answer» Correct Answer - D `A=(0.1)^(2) = 0.01m^(2),.^ (eta=0.01 "Poise" = 0.001 "decapoise") (M.K.S. "unit")`, `dupsilon = 0.1m//s` and `F = 0.002N` `F=etaA(dv)/(dx) " "therefore dx = (etaAdv)/(F) = (0.001xx0.01xx0.01)/(0.002) = 0.0005m`. |
|