1.

A square park has its side 32 m. At each corner of the park, there is a flower bed in the form of a quadrant of radius 10 m as shown in the figure. Find the area of the remaining part of the park. (Take π = 3.14)​

Answer»

Here, Required Area

= Area of square - Area of 4 quadrants.

Radius of ONE Quadrant = 10 m

Therefore Area of 4 Quadrants

= \frac{\pi {r}^{2} }{4} \times 4 \\ \\ = 3.14 \times 10 \times 10 \\ \\ = 314 \: \: {m}^{2}

Now, Required Area

= {32}^{2} - 314 \\ \\ = 1024 - 314 \\ \\ = 710 \: {m}^{2}

Hence, Area of remaining part = 710 meter SQ.


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