1.

A square loop of wireof side 5 cm is lying on a horizontal table. Anelectromagnet above and to one side of the loop is turned on, causing a uniform magnetic field downwards at an angle of 60^@ to the vertical as shown in figure. The magnetic induction is 0.50 T. The average induced emf in the loop, if the field increases from zero to its final value in 0.2 s is

Answer»

`5.4xx10^(-3)` V
`3.12xx10^(-3)` V
`0`
`0.25xx10^(-3)` V

Solution :The average INDUCED e.m.f. in the loop is ,
`epsilon=(dphi)/(dt)=((NBA cos theta - 0))/t`
`=(1xx0.5xx25xx10^(-4) cos 60^@-0)/0.2` or `epsilon= 3.12xx10^(-3)` V


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