A square loop of side 20 cm is placed in a magnetic field B=(5+2t2); such that, the magnetic field is perpendicular to the plane of the loop. If resistance of loop is 2Ω, heat generated in 5 sec in joules is (write until two digits after the decimal point)

A square loop of side 20 cm is placed in a magnetic field B=(5+2t2); s

1.	A square loop of side 20 cm is placed in a magnetic field B=(5+2t2); such that, the magnetic field is perpendicular to the plane of the loop. If resistance of loop is 2Ω, heat generated in 5 sec in joules is (write until two digits after the decimal point)
Answer» A square loop of side 20 cm is placed in a magnetic field $B = (5 + 2 t^{2})$ ; such that, the magnetic field is perpendicular to the plane of the loop. If resistance of loop is $2 Ω$ , heat generated in 5 sec in joules is (write until two digits after the decimal point)

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A square loop of side 20 cm is placed in a magnetic field B=(5+2t2); such that, the magnetic field is perpendicular to the plane of the loop. If resistance of loop is 2Ω, heat generated in 5 sec in joules is (write until two digits after the decimal point)

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