Saved Bookmarks
| 1. |
A square conductind loop, `20.0 cm` on a side placed in the same magnetic field as shown in Fig. 3.195, center of the magnetic field region, where `dB//dt = 0.035 T s^(-1)`. The current induced in the loop if its resistance is `2.00 Omega` isA. (a) `2.50 xx 10^(-4) A`B. (b) `4.35 xx 10^(-4) A`C. ( c) `1.25 xx 10^(-4) A`D. (d) `7.37 xx 10^(-4) A` |
|
Answer» Correct Answer - D (d) `I = (epsilon)/(R ) = (A)/(R )(dB)/(dt) = (L^(2))/(R )(dB)/(dt)` `= ((0.20 m)^(2)(0.0350 T //s))/(1.90 Omega)` `= 7.37 xx 10^(-4) A` |
|