A square coil of `10^(-2) m^(2)` area is placed perpenducular to a uniform magnetic field of `10^(3) Wb//m^(2)`. What is magnetic flux through the coil?

A square coil of `10^(-2) m^(2)` area is placed perpenducular to a uni

1.	A square coil of `10^(-2) m^(2)` area is placed perpenducular to a uniform magnetic field of `10^(3) Wb//m^(2)`. What is magnetic flux through the coil?
Answer» Here, `A = 10^(-2) m^(2), B = 10^(3) Wb//m^(2)` `theta = 0^(@), phi = ?` `phi = BA cos theta = 10^(3) xx 10^(-2) cos 0^(@) = 10` Weber

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A square coil of `10^(-2) m^(2)` area is placed perpenducular to a uniform magnetic field of `10^(3) Wb//m^(2)`. What is magnetic flux through the coil?

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