A square brass plate of side 1m and thickness 0.005m is subjected a forces f on its smaller opposite edges causing a displacement 0.2cm if the shear modulus is 0.4×10^11 value of force f?

A square brass plate of side 1m and thickness 0.005m is subjected a fo

1.	A square brass plate of side 1m and thickness 0.005m is subjected a forces f on its smaller opposite edges causing a displacement 0.2cm if the shear modulus is 0.4×10^11 value of force f?
Answer» e,● Answer-F = 1.6×10^10 N● Explaination-# Given-A = 1 m^2h = 0.005 mx = 0.002 mη = 0.4×10^11# Solution-SHEARING MODULUS is CALCULATED by -Shearing modulus = Shearing stress / shearing stressη = (F/A) / (x/h)F = η × A × x / hF = 0.4×10^11 × 1 × 0.002 / 0.005F = 1.6×10^10 NTherefore, force of 1.6×10^10 N is USED for shearing.Hope it helps...

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A square brass plate of side 1m and thickness 0.005m is subjected a forces f on its smaller opposite edges causing a displacement 0.2cm if the shear modulus is 0.4×10^11 value of force f?

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