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A spring of weight W and force constant k is suspended in a horizontal position by two light strings attached to its two ends. Each string makes an angle θ with the vertical. The extension of the spring is (a) (W/4k)tan θ(b) (W/2k)tan θ(c) (W/4k)sin θ (d) 0 |
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Answer» Correct Answer is: (b) (W/2k)tan θ Let T = tension in each string. 2Tcos θ = W and Tsin θ = kx, x = extension of spring or (W/2cos θ) sin θ = kx or x = w tan /2k. |
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