1.

a spring of force constant 1500nm-2 is acted upon by a constant force of 75N. calculate the potential energy stored in the spring

Answer»

EXPLANATION:

u = 1 \div 2kx { }^{2} \\ u = 1 \div 2 \times 75 \times 75 \div 1500 \\ u = 1.875

x = f \div k

f =  - kx \\



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