1.

a spring is stretched by 50mm by applying a force the work done by the spring is. if the force required for stretching 1 mm of the spring is 10N​

Answer»

QUESTION:

A spring 50mm long spring is stretched by APPLYING a force. If 10N force is required to stretch the spring through 1 MM, then work done in STRETCHING the spring through 50mm is

Given:

Force (to stretch 1mm) = 10N

To Find:

Work done by stretching 50mm.

Solution:

Force constant,

\sf{k = \dfrac{F}{x} = \dfrac{10}{0.001}=10⁴ N/m}

\bold{Work\: done = \dfrac{1}{2}kx²}

\bold{ = \dfrac{1}{2}×10⁴×(\dfrac{5\cancel{0}}{100\cancel{0}})²}

\bold{ = \dfrac{1}{2}×\cancel{10⁴}×\dfrac{25}{\cancel{10⁴}}}

=\bold{\red{ 12.5 J}}

∴ Work done by stretching the spring by 50mm is 12.5J.


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