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A spring is stretched by 2 cm by an object attached to It near the surface of earth. How much extension of the same spring take place by the same object when taken to a point 3,200 km above the surface of earth (Radius of earth = 6,400 km) |
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Answer» 0.5 cm At a height of 3, 200 KM above earth.s surface `mg. = k (y)` As `g = (GM)/(R^(2))` `g. = (GM)/((R+h)^(2))` `(g.)/(g) = (k y)/(k (2)) = (R^(2))/((R+h)^(2))` `y = (2 cm)((R )/((R+h)))^(2)` `= 2cm ((6,400 km)/(6,400 km + 3,200 km))^(2)` `= 2((6,400)/(9,600))^(2) = 0.9 cm` |
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