(a) Splitting the given figure into therectangles I and II, we getArea

1.	(a) Splitting the given figure into therectangles I and II, we getArea of the rectangle != 12 cm x 2 cm = 24 sq cmArea of the rectangle Il= 8 cm x 2 cm = 16 sq cm2I10128(10-2) = 8 II 210:: Total area of the whole figure = 24 sq cm +16 sq cm = 40 sq cm.
Answer» ANSWER: Q20. H.C.F of two numbers is 4 and L.C.M there is 180. If one of the numbers is 36, FIND the other.

(a) Splitting the given figure into therectangles I and II, we getArea of the rectangle != 12 cm x 2 cm = 24 sq cmArea of the rectangle Il= 8 cm x 2 cm = 16 sq cm2I10128(10-2) = 8 II 210:: Total area of the whole figure = 24 sq cm +16 sq cm = 40 sq cm.

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ANSWER:

Q20. H.C.F of two numbers is 4 and L.C.M there is 180. If one of the numbers is 36, FIND the other.

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(a) Splitting the given figure into therectangles I and II, we getArea of the rectangle != 12 cm x 2 cm = 24 sq cmArea of the rectangle Il= 8 cm x 2 cm = 16 sq cm2I10128(10-2) = 8 II 210:: Total area of the whole figure = 24 sq cm +16 sq cm = 40 sq cm.​

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(a) Splitting the given figure into therectangles I and II, we getArea of the rectangle != 12 cm x 2 cm = 24 sq cmArea of the rectangle Il= 8 cm x 2 cm = 16 sq cm2I10128(10-2) = 8 II 210:: Total area of the whole figure = 24 sq cm +16 sq cm = 40 sq cm.