A sphericalbodymovingwith a speed of 10 m/s strikesanother identicalbody at rest such that after collision , the directionof motionof eachball makesan angleof15^(@) with theoriginaldirection of motion . Calculate the speedof eachbody aftercollision.

A sphericalbodymovingwith a speed of 10 m/s strikesanother identicalbo

1.	A sphericalbodymovingwith a speed of 10 m/s strikesanother identicalbody at rest such that after collision , the directionof motionof eachball makesan angleof15^(@) with theoriginaldirection of motion . Calculate the speedof eachbody aftercollision.
Answer» Solution :Massof eachbody = m The givencollisionprocess is shown below: Here `u_(1)`and `u_(2)`areintialspeedsof body moving with 10 m/sand THATOF body , RESPECTIVELY. `v_(1) and v_(2)`are speedsof the bodyafter COLLISION Usinglawof conservation of MOMENTUM alongtheline of motion , `"mu"_(1) + "mu"_(2) = mv_(1) COS 15^(@) +mv_(2) cos15^(@)` `mxx 10 + 0 = mxxv_(1) xx 0.966 +mv_(2) xx0.966` ` 10 m = m xx 0.966 (v_(1) +v_(2))` ` rArr"" v_(1) +v_(2) = 10.35.....(i)` Now usinglawofconservationof momentumalong thedirectionperpendicularto the original line of motion , ` m xx 0 + m xx 0 = mv_(1) sin 15^(@) -mv_(2) sin 15^(@)` ` rArr "" v_(1) sin 15^(@) = v_(2) sin 15^(@)` or `v_(1) =v_(2) ""...(ii)` Using (i) and (ii) , we get ` rArr v_(1) = 5.175 ` m/s ` rArr "" v_(2) = 5.175 ` m/s