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A spherical steel ball released at the topp of a long column of glycerine of length l falls through a distance l//2 with accelerated motion and the remaining distance l//2 with uniform velocity V. Let t_(1) and t_(2) denote the times taken to cover the first and second half and W_(1) and W_(2) the work done agaist gravity in the two halves, then compare times and work done. |
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Answer» Solution :The AVERAGE VELOCITY in the first half of the distance `ltv`, while in the second half the average velocity is v. There fore, `t_(1s)gtt_(2)`. The workdone against gravity in both halves is `MG l//2` `:.t_(1s)gt_(2)""w_(1)=w_(2)` |
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