A spherical iron ball is dropped into a cylindrical vessel of base dia

1.	A spherical iron ball is dropped into a cylindrical vessel of base diameter 14 cm, containing water. The water level is increased by \(9\frac{1}{3}\) cm. What is the radius of the ball?(a) 3.5 cm (b) 7 cm (c) 9 cm (d) 12 cm
Answer» Answer : (b) = 7 cm Let R be the radius of the ball. Then, Volume of water displaced = Volume of iron ball ⇒ \(\pi \times \big(\frac{14}{2}\big)^2 \times \frac{28}{3} = \frac{4}{3} \times\pi \times R^3\) ⇒ R³ = 7³ ⇒ R = 7.

A spherical iron ball is dropped into a cylindrical vessel of base diameter 14 cm, containing water. The water level is increased by \(9\frac{1}{3}\) cm. What is the radius of the ball?(a) 3.5 cm (b) 7 cm (c) 9 cm (d) 12 cm

Answer»

Answer : (b) = 7 cm

Let R be the radius of the ball.

Then,

Volume of water displaced = Volume of iron ball

⇒ \(\pi \times \big(\frac{14}{2}\big)^2 \times \frac{28}{3} = \frac{4}{3} \times\pi \times R^3\)

⇒ R³ = 7³

⇒ R = 7.