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A spherical drop of water as `1mm` radius. If the surface tension of the the water is `50xx10^-3(N)/(m)`, then the difference of pressure between inside and outside the spherical drop is:A. `25 N//m^(2)`B. `10000 N//m^(2)`C. `100 N//m^(2)`D. `50 N//m^(2)` |
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Answer» Correct Answer - C `P_("excess")=(2T)/R=(2(50xx10^(-3)))/((10^(-3)))=100 N//m^(2)` |
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