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A sphere of radius 10 cm carries a charge of 1micro coulomb. calculate the electric fielt intensitya) at a Istance 30cm from the centre of the sphereb) at the surface of the Spherec) of a distance of 5 cm from the centre of the sphere |
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Answer» Answer: Repulsive force of magnitude 6 × 10−3 N Charge on the first sphere, q1 = 2 × 10−7 C Charge on the second sphere, q2 = 3 × 10−7 C Distance between the spheres, R = 30 cm = 0.3 m Electrostatic force between the spheres is given by the relation: F = (1/4πε0). (q1q2)/ (r2) Where, ε0 = Permittivity of FREE space and (1/4πε0) =9 × 109 Nm2C−2 Therefore, force F = (9 × 109 × 2 × 10−7)/ ((0.3)2) = 6 × 10−3N Hence, force between the two small charged spheres is 6 × 10−3 N. The charges are of same nature. Hence, force between them will be repulsive. |
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