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A sphere of mass 50 xx 10^(-3)kg moving with a velocity of 2ms^(-1) hits another sphere which is at rest. Assuming the collision to be head-on collision and if they stick together after collision and move in the same direction with a velocity of 0.5 ms^(-1), find the mass of the second sphere

Answer»

SOLUTION :`m_(1) = 50 xx 10^(-3) KG, u_(1)= 2ms^(-1), u_(2)= 0, v= 0.5 ms^(-1), v= v_(1)= v_(2)= 0.5 ms^(-1)`
`m_(1)u_(1) + m_(2) u_(2)= (m_(1) + m_(2))v`
`(50 xx 10^(-3))(2) + m_(2) (0) =[(50 xx 10^(-3))+ m_(2)] 0.5`
`m_(2)= (50 xx 10^(-3) xx 2 - 50 xx 10^(-3) xx 0.5)/(0.5)`
`=((100-25))/(0.5) xx 10^(-3)= 150 xx 10^(-3) kg`


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