1.

A sphere of lead of diameter 6 cm is melted and recast into three spherical balls. Thediameters of these are 3 cm and 4 cm respectively. Then, the diameter of third one is(a) 8 cm (b) 10 cm(c) 5 cm (d) 15 cm​

Answer»

Answer:

5 cm

Step-by-step explanation:

VOLUME of SPHERE=(4/3)πr³

In given lead sphere,

radius =6/2=3cm

volume =(4/3)π3³cm³

for small spherical balls

volume of 1ST ball =(4/3)π(3/2)³

volume of 2nd ball =(4/3)π2³

let radius of 3rd sphere be r

then it's volume =$4/3)πr³

Now ACCORDING to question,

(4/3)π3³=(4/3)π27/8. +(4/3)π8 +(4/3)πr³

(4/3)π27=(4/3)π (27/8 + 8 + r³)

27=27/8 +8 +r³

19=27/8 + r³

(152-8)/8=r³

18=r³

r ~ 2.2

diameter =5cm APPROXIMATELY



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