A speaks truth in 25% of cases and B in 20% of cases. In what percenta

1.	A speaks truth in 25% of cases and B in 20% of cases. In what percentage of cases are they likely to agree with each other, narrating the same incident?Select one:a. 60%b. 65%c. 45%d. 5%
Answer» $\huge\red{Answer}$ $\text{[math]}$ ➡️*Let A = Event that A SPEAKS the truth* *B = Event that B speaks the truth* *B = Event that B speaks the truthThen P(A) = 25/100 = 1/4* *P(B) = 20/100 = 1/5* *P(B) = 20/100 = 1/5P(A-lie) = 1-1/4 = 1/4* . *P(B-lie) = 1-1/5 = 1/5* *P(B-lie) = 1-1/5 = 1/5Now* *A and B contradict each other =* *[A lies and B true] or [B true and B lies]* *= P(A).P(B-lie) + P(A-lie).P(B)* *[PLEASE note that we are adding at the. place of OR]* **= (3/51/5) + (1/44/5) = 7/20 = (7/20 100) % = 35%*** ¯\_(ツ)_/¯

A speaks truth in 25% of cases and B in 20% of cases. In what percentage of cases are they likely to agree with each other, narrating the same incident?Select one:a. 60%b. 65%c. 45%d. 5%

Answer»

$\huge\red{Answer}$

$\text{[math]}$

➡️Let A = Event that A SPEAKS the truth B = Event that B speaks the truth

B = Event that B speaks the truthThen P(A) = 25/100 = 1/4 P(B) = 20/100 = 1/5

P(B) = 20/100 = 1/5P(A-lie) = 1-1/4 = 1/4 . P(B-lie) = 1-1/5 = 1/5

P(B-lie) = 1-1/5 = 1/5Now

A and B contradict each other =

[A lies and B true] or [B true and B lies]

= P(A).P(B-lie) + P(A-lie).P(B)

[PLEASE note that we are adding at the. place of OR]

= (3/5*1/5) + (1/4*4/5) = 7/20

= (7/20 * 100) % = 35%

¯\_(ツ)_/¯

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A speaks truth in 25% of cases and B in 20% of cases. In what percentage of cases are they likely to agree with each other, narrating the same incident?Select one:a. 60%b. 65%c. 45%d. 5%

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