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A source producing a sound of frequency 500 Hz is moving towards is listener with a velocity of 30 ms^(-1). The speed of the sound is 330ms^(-1). What will be the frequency heard by listener? |
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Answer» Solution :When the source is moving towards the stationary listener, the EXPRESSION for APPARENT frequency is `N.=((v)/(v-v_(s)))n` `=((330)/(330-30))xx500` `=550Hz` |
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