1.

A source producing a sound of frequency 500 Hz is moving towards is listener with a velocity of 30 ms^(-1). The speed of the sound is 330ms^(-1). What will be the frequency heard by listener?

Answer»

Solution :When the source is moving towards the stationary listener, the EXPRESSION for APPARENT frequency is
`N.=((v)/(v-v_(s)))n`
`=((330)/(330-30))xx500`
`=550Hz`


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