Saved Bookmarks
| 1. |
A sound wave of frequency `500 Hz` cobers a distance of 1000 m in 5 s between the points X and Y. The number of waves between X and Y is :A. 500B. 1000C. 2500D. 5000 |
|
Answer» Correct Answer - C Number of waves emitted in `5 s = 500 xx 5 = 2500` Aliter `v = (1000m)/(5 s) = 200 m//s, v = 500 Hz` `lamda = (v)/(v) = (200 m//s)/(500 Hz) = (2)/(5) m` Number of waves in `1000 m = (1000 m)/((2//5) m) = 2500`. |
|