1.

A solution saturated in lime water has a pH of 12 Then the `K_(sp)` for `Ca(OH)_(2)` is `:`A. `3.2xx10^(-3)`B. `1.25xx10^(-7)`C. `1.00xx10^(-7)`D. `3.2xx10^(-4)`

Answer» Correct Answer - 2
`pH=12" "implies" "-log(H^(+))=12implies`
`log[H^(+)]-12" "Ca(OH)_(2)hArr2OH^(-)+Ca^(2+)`
`[H^(+)]=10^(-12)`
`[OH^(-)]=(10^(-4))/(10^(-14))=10^(-2)`
`K_(sp)=[Ca^(2+)][OH^(-)]^(-2)" "[Ca^(2+)]=(1)/(2)[OH^(-)]`
`(10^(-2))xx((1)/(2)xx10^(-2))^(2)=1.25xx10^(-7)Ans.`


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