1.

A solution of substance containing `1.05` g per 100 mL was found to be isotonic with `3%` glucose solution . The molecular mass of the substance is :A. 31.5B. 6.3C. 630D. 63

Answer» Correct Answer - D
`(1.05)/(Mw)xx10=(3)/(180)xx10`
`Mw=1.05xx60=63`


Discussion

No Comment Found

Related InterviewSolutions