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A solution of sodium chloride discharge `6.0 xx 10^(16)Na^(+) and 4.5 xx 10^(16)Cl^(-1)` lons in `2` seconds. What is the current passing through the solution ? |
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Answer» Correct Answer - ` 8.4 mA` `I = I_(Na)+ I_(C) = (n_(Na)+ n_(Cl)) e//t` `= ((6.0 xx 10^(16)+ 4.5 xx 10^(16)) xx 1.6 xx 10^(-19))/(2)` `= 8.4 xx 10^(-3)A = 8.4 mA` |
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